Chem 103 module 2 Study guides, Class notes & Summaries

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 CHEM 103 module 2 notes MOLECULAR WEIGHT
  • CHEM 103 module 2 notes MOLECULAR WEIGHT

  • Other • 26 pages • 2023
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  • : MOLECULAR WEIGHT A compound is made up of two or more elements combined in a definite ratio that is represented by a molecular formula. Each of these elements has a certain atomic weight, which can be found in the periodic table. The sum of the atomic weights of the atoms in the molecular formula is called the formula weight or molecular weight or formula mass. We will use the term molecular weight for this number in our work. Here are three examples of molecular weight determination: C...
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CHEM 103 MODULE 2 EXAM 202
  • CHEM 103 MODULE 2 EXAM 202

  • Exam (elaborations) • 7 pages • 2023
  • CHEM 103 MODULE 2 EXAM 2022 Question 1 Click this link to access the Periodic Table. This may be helpful throughout the exam. Show the calculation of the molecular weight for the following compounds, reporting your answer to 2 places after the decimal. 1. Al2(CO3)3 2. C8H6NO4Cl 1. 2Al + 3C + 9O = 23
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CHEM 103 MODULE 2 EXAM .
  • CHEM 103 MODULE 2 EXAM .

  • Exam (elaborations) • 7 pages • 2023
  • CHEM 103 MODULE 2 EXAM .Question 2 Click this link to access the Periodic Table. This may be helpful throughout the exam. Show the calculation of the number of moles in the given amount of the following substances. Report your answerto 3 significant figures. 1. 13.0 grams of (NH4)2CO3 2. 16.0 grams of C8H6NO4Br 1. Moles = grams / molecular weight = 13.0 / 96.09 = 0.135 mole 2. Moles = grams / molecular weight = 16.0 / 260.04 = 0.0615 mole Question 3 Click this link to access the Periodic T...
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CHEM 103 Module 2 Exam (General Chemistry) – Portage Learning
  • CHEM 103 Module 2 Exam (General Chemistry) – Portage Learning

  • Exam (elaborations) • 19 pages • 2023
  • CHEM 103 Module 2 Exam (General Chemistry) – Portage Learning. Al (SO ) Al = 2 x 26.98 = 53.96 S = 3 x 32.07 = 96.21 O = 12 x 16.00 = 192 2 4 3 M2: Exam - Requires Respondus LockDown Browser + Webcam: General Chemistry I w/Lab-2021- Kozminski 3/18 Total Molecular Weight for Al (SO ) = 342.17 2. C H NOBr C = 7 x 12.01 = 84.07 H = 5 x 1.008 = 5.04 N = 1 x 14.01 = 14.01 O = 1 x 16.00 = 16.00 Br = 1 x 79.90 = 79.90 Total Molecule Weight for C H NOBr= 199.02
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CHEM 103 Module 2 exam with correct answers Latest Updated Examination study Guide 2024
  • CHEM 103 Module 2 exam with correct answers Latest Updated Examination study Guide 2024

  • Exam (elaborations) • 8 pages • 2024
  • CHEM 103 Module 2 exam with correct answers Latest Updated Examination study Guide 2024
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Chem 103 Module 2 Study Questions with Answers
  • Chem 103 Module 2 Study Questions with Answers

  • Exam (elaborations) • 6 pages • 2024
  • atom Basic unit of matter; made of protons, neutrons, and electrons; have a nucleus that contains p and n and an electron cloud that surrounds it proton A subatomic particle that has a positive charge and that is found in the nucleus of an atom neutron A subatomic particle that has no charge and that is found in the nucleus of an atom electron A subatomic particle that has a negative charge and is found outside of the nucleus masses of subatomic particles the proton and neutron have ...
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CHEM 103 MODULE 2 RATED A+
  • CHEM 103 MODULE 2 RATED A+

  • Exam (elaborations) • 9 pages • 2023
  • CHEM 103 MODULE 2 RATED A+ Question 1 10 / 10 pts Click this link to access the Periodic Table. This may be helpful throughout the exam. Show the calculation of the molecular weight for the following compounds, reporting your answer to 2 places after the decimal. 1. (NH4)2CO3 2. C8H6NO4Br Your Answer: 1. (NH4)2CO3 =96.09 grams N = 14.01 x 2 2(14.01) + 8(1.008)+3(16.0) = 96.09grams H = 1.008 x 8 C = 12.01 x 1 O = 16 x 3 = 96.09grams 2. C8H6NO4Br = 260.04grams C= 12.01 x 8 8(12.01) + 6(1...
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CHEM 103 Module 2 Exam (General Chemistry) – Portage Learning
  • CHEM 103 Module 2 Exam (General Chemistry) – Portage Learning

  • Exam (elaborations) • 19 pages • 2023
  • Available in package deal
  • CHEM 103 Module 2 Exam (General Chemistry) – Portage Learning. Show the calculation of the molecular weight for the following compounds, reporting your answer to 2 places after the decimal. 1. Al (SO ) 2. C H NOBr 2 4 3 7 5 1. Al (SO ) Al = 2 x 26.98 = 53.96 S = 3 x 32.07 = 96.21 O = 12 x 16.00 = 192 2 4 3 M2: Exam - Requires Respondus LockDown Browser + Webcam: General Chemistry I w/Lab-2021- Kozminski 3/18 Total Molecular Weight for Al (SO ) = 342.17 2. C H NOBr C = 7 x 12.01 ...
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CHEM 103 Module 2 Problem Set (100 out of 100) Questions and Verified Elaborations | GRADED A
  • CHEM 103 Module 2 Problem Set (100 out of 100) Questions and Verified Elaborations | GRADED A

  • Exam (elaborations) • 6 pages • 2024
  • CHEM 103 Module 2 Problem Set (100 out of 100) Questions and Verified Elaborations | GRADED A
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PORTAGE LEARNING CHEM 103 MODULE 2 EXAM 2022
  • PORTAGE LEARNING CHEM 103 MODULE 2 EXAM 2022

  • Exam (elaborations) • 7 pages • 2023
  • PORTAGE LEARNING CHEM 103 MODULE 2 EXAM 2022
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