Chem 121 Study guides, Class notes & Summaries

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CHEM 121 Lab Report 5: Bonding Type by Solubility, Distillation, and Spectroscopy
  • CHEM 121 Lab Report 5: Bonding Type by Solubility, Distillation, and Spectroscopy

  • Exam (elaborations) • 10 pages • 2023
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CHEM 121 Lab Report 6: Measuring Kand Shifting Chemical Equilibria
  • CHEM 121 Lab Report 6: Measuring Kand Shifting Chemical Equilibria

  • Exam (elaborations) • 8 pages • 2023
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CHEM 121 Lab Report 9: Inorganic Synthesis
  • CHEM 121 Lab Report 9: Inorganic Synthesis

  • Exam (elaborations) • 6 pages • 2023
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CHEM 121 Lab Report 7: Acid Base Titrations
  • CHEM 121 Lab Report 7: Acid Base Titrations

  • Exam (elaborations) • 5 pages • 2023
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CHEM 121 Exam 2 SPRING 2024 Portage learning
  • CHEM 121 Exam 2 SPRING 2024 Portage learning

  • Exam (elaborations) • 39 pages • 2024
  • Show the calculation of the molecular weight for the following two compounds, reporting your answer to 2 places after the decimal. 1. Ca3(PO4)2 2. C9H8NO4Cl Your Answer: 1. 3(40.08)+2(30.97+4(16))=310.18 g/mol Ca3(PO4)2 2. 9(12.01)+8(1.008)+14.01+4(16)+35.45 = 229.61 g/mol C9H8NO4Cl 1. 3Ca + 2P + 8O = 310.18 2. 9C + 8H + N + 4O + Cl = 229.61 Question 2 9 / 10 pts You may find the following resources helpful: Scientific Calculator Links to an external site. Periodic Table Equation ...
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CHEM 121 Exam 1 SPRING 2024 Portage learning
  • CHEM 121 Exam 1 SPRING 2024 Portage learning

  • Exam (elaborations) • 17 pages • 2024
  • Complete the two problems below: 1. Convert 845.3 to exponential form and explain your answer. 2. Convert 3.21 x 10-5 to ordinary form and explain your answer. Your Answer: 8.453x10^2 - the decimal point was moved two places to the left - the first number was 8 .0000321 - the decimal point needed to be moved five spaces to the left. 1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places = 8.453 x 102 2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move ...
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CHEM 121 Module 5 exam (Portage learning) SPRING 2024
  • CHEM 121 Module 5 exam (Portage learning) SPRING 2024

  • Exam (elaborations) • 19 pages • 2024
  • In the reaction of gaseous N O to yield NO gas and O gas as shown below the following data table is obtained: 2 N O (g) → 4 NO (g) + O (g) 2 5 2 2 2 5 2 2 Your Answer: Data Table #2 Time (sec) [N O ] [O ] 0 0.300 M 0 300 0.272 M 0.014 M 600 0.224 M 0.038 M 900 0.204 M 0.048 M 1200 0.186 M 0.057 M 1800 0.156 M 0.072 M
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CHEM 121 Module 4 exam (Portage learning) SPRING 2024
  • CHEM 121 Module 4 exam (Portage learning) SPRING 2024

  • Exam (elaborations) • 15 pages • 2024
  • Show the determination of the charge on the ion formed by the Mg12 atom. Mg has a +2 charge S 2S 2P 3S also you can just look at the periodic table and see that it is in collumn 2 on the left side and would know that it has a +2 charge because the 2 columns on the left are + this is day 1 chem 101 knowledge 12 2 2 6 2 Mg (metal = lose electrons) 1s 2s 2p 3s lose 2e → Mg 12 2 2 6 2 +2 Ques 10 / 10 pts tion 2
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CHEM 121 Lab 2 Density SPRING 2024 Portage learning
  • CHEM 121 Lab 2 Density SPRING 2024 Portage learning

  • Other • 11 pages • 2024
  • Experiment #: 2 Title: Density Purpose: To measure the density of some liquids and solids which includes some materials of biological interest. Procedure: 1. Dispense 10mL of water using a 10mL pipet into beaker on zeroed scale 2. Use scale to measure mass of water 3. Calculate density 4. Add 5mL of water to beaker using a 5mL pipet 5. Use scale to measure mass of water 6. Calculate Density 7. Add 10mL of water to beaker using a 10mL pipet 8. Use scale to measure mass of water 9. Ca...
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