Chem 103 module 2 Study guides, Class notes & Summaries

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CHEM 103 Module 3 Exam Portage Learning 2023
  • CHEM 103 Module 3 Exam Portage Learning 2023

  • Exam (elaborations) • 11 pages • 2023
  • CHEM 103 Module 3 Exam Portage Learning 2023. NH4Cl is being dissolved in water and this process is being studied in a styrofoam coffee cup with a lid and the heat absorbed is measured by means of a thermometer immersed in the reaction mixture. Enter the correct thermochemistry term to describe the item listed. 1. The type of thermochemical process 2. The air above the cup Your Answer: 1) endothermic 2) Surroundings 1. Heat absorbed = Endothermic process 2. The air above the cup = Surro...
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CHEM 103 Module 2 Problem Set (100 out of 100) Questions and Verified Elaborations (GRADED A)
  • CHEM 103 Module 2 Problem Set (100 out of 100) Questions and Verified Elaborations (GRADED A)

  • Exam (elaborations) • 6 pages • 2024
  • CHEM 103 Module 2 Problem Set (100 out of 100) Questions and Verified Elaborations (GRADED A)
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Portage Learning - CHEM 103 MODULE 2 Exam
  • Portage Learning - CHEM 103 MODULE 2 Exam

  • Exam (elaborations) • 16 pages • 2023
  • Portage Learning - CHEM 103 MODULE 2 Exam Click this link to access the Periodic Table. This may be helpful throughout the exam. Show the calculation of the molecular weight for the following compounds, reporting your answer to 2 places after the decimal.
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CHEM 103 General Chemistry Module 1, 2, 3, 4, 5, 6 Exam (Latest-2023)/ CHEM103 General Chemistry Module 1, 2, 3, 4, 5, 6  Exam: Portage Learning |100% Correct Q & A|
  • CHEM 103 General Chemistry Module 1, 2, 3, 4, 5, 6 Exam (Latest-2023)/ CHEM103 General Chemistry Module 1, 2, 3, 4, 5, 6 Exam: Portage Learning |100% Correct Q & A|

  • Exam (elaborations) • 35 pages • 2023
  • CHEM 103 General Chemistry Module 1, 2, 3, 4, 5, 6 Exam (Latest-2023)/ CHEM103 General Chemistry Module 1, 2, 3, 4, 5, 6 Exam: Portage Learning |100% Correct Q & A|
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Portage Learning - CHEM 103 MODULE 2 Exam
  • Portage Learning - CHEM 103 MODULE 2 Exam

  • Exam (elaborations) • 15 pages • 2023
  • Portage Learning - CHEM 103 MODULE 2 Exam
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CHEM 103 MODULE 2 EXAM 202
  • CHEM 103 MODULE 2 EXAM 202

  • Exam (elaborations) • 7 pages • 2023
  • CHEM 103 MODULE 2 EXAM 2022 Question 1 Click this link to access the Periodic Table. This may be helpful throughout the exam. Show the calculation of the molecular weight for the following compounds, reporting your answer to 2 places after the decimal. 1. Al2(CO3)3 2. C8H6NO4Cl 1. 2Al + 3C + 9O = 233.99
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CHEM 103 Module 2 exam with correct answers
  • CHEM 103 Module 2 exam with correct answers

  • Exam (elaborations) • 8 pages • 2023
  • CHEM 103 Module 2 exam with correct answersCHEM 103 Module 2 exam with correct answersCHEM 103 Module 2 exam with correct answers
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Chem 103 Module 2 Exam with Correct Answers 2024 Examination study guide||Latest 2024
  • Chem 103 Module 2 Exam with Correct Answers 2024 Examination study guide||Latest 2024

  • Exam (elaborations) • 8 pages • 2024
  • Chem 103 Module 2 Exam with Correct Answers 2024 Examination study guide||Latest 2024
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CHEM 103 Module 2 exam with correct answers.
  • CHEM 103 Module 2 exam with correct answers.

  • Exam (elaborations) • 8 pages • 2023
  • CHEM 103 Module 2 exam with correct answers.
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Docu PORTAGE LEARNING CHEM 103 MODULE 4EXAM 2023 WITH QUESTIONS AND CORRECT ANSWERS 100% PASS,PERIODIC TABLE IN THE LAST PAGE 2024ment title]
  • Docu PORTAGE LEARNING CHEM 103 MODULE 4EXAM 2023 WITH QUESTIONS AND CORRECT ANSWERS 100% PASS,PERIODIC TABLE IN THE LAST PAGE 2024ment title]

  • Exam (elaborations) • 40 pages • 2024
  • Docu PORTAGE LEARNING CHEM 103 MODULE 4EXAM 2023 WITH QUESTIONS AND CORRECT ANSWERS 100% PASS,PERIODIC TABLE IN THE LAST PAGE 2024ment title]MODULE 1 EXAM Convert 845.3 to exponential form and explain your answer. 1. Convert 3.21 x 10-5 to ordinary form and explain your answer. 1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places = 8.453 x 102 2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 places = 0.0000321 Question 2 ...
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